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B.P.T.

Basic proportionality theoram (B.P.T.)
Statement:
If the line parallel to the side of the triangle intersects other sides in two distinct points then the other sides are divide in the same ratio by it.
     

Given:
In ∆PQR, line l॥ side QR and intersects side PQ and side PR in points M and N respectively. 
     P-M-Q and P-N-R.

To Prove:
               
Construction:
Join seg QN and seg RM
 Proof:

In ∆PMN and ∆QMN,
.......(1) (triangles having equal heights).

      In ∆PMN and ∆RMN,
Ashok........(2) (triangles having equal heights).
 
ஃ A(∆QMN)=A(∆RMN)....(3) (triangles with common base and equal height).

......(4). (from (1)..(2).&(3).)  
ஃ (from (1)..(2)..&..(4)...)

.
.
Thank you
Ashok Kadam.


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